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5k^2=12k+2
We move all terms to the left:
5k^2-(12k+2)=0
We get rid of parentheses
5k^2-12k-2=0
a = 5; b = -12; c = -2;
Δ = b2-4ac
Δ = -122-4·5·(-2)
Δ = 184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{184}=\sqrt{4*46}=\sqrt{4}*\sqrt{46}=2\sqrt{46}$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{46}}{2*5}=\frac{12-2\sqrt{46}}{10} $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{46}}{2*5}=\frac{12+2\sqrt{46}}{10} $
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